Botic van de Zandschulp recovered from two sets down and saved a match point to beat Arthur Gea in five hours and thirteen minutes. Their September 7, 2026 US Open fourth-round match finished 3-6, 6-7(0), 7-6(7), 7-6(3), 6-4.
After losing every point in the second-set tiebreak, Van de Zandschulp won the next two tiebreaks 9-7 and 7-3. He closed the final set 6-4 to return to the US Open quarterfinals, a stage he had reached in 2021.
Both players broke serve seven times. Gea converted seven of sixteen break points; Van de Zandschulp converted seven of twenty-one. Gea saved fourteen of twenty-one break points and Van de Zandschulp nine of sixteen.
The Australian Open’s official report dated September 9 described it as the tournament’s fourth-longest match. Lucky loser Gea had been one point from the first major men’s singles quarterfinal by a lucky loser, while Van de Zandschulp matched his own best Grand Slam result.
